Answer:
ΔCAB~ΔFDE (translated as "triangle CAB is similar to triangle FDE)
Explanation:
One way to prove triangle similarity is by the AA (Angle-Angle) postulate, which means that two interior angles of one triangle are Congruent to two interior angles in another triangle. Since both triangles are Right triangles, they both have right angles in them. And using the Triangle Sum theorem (the sum of the measures of all three interior angles of a triangle is 180°), we can determine that m∠A=55°, making ∠A≅∠D.
In a nutshell, since ∠C≅∠F and ∠A≅∠D, ΔCAB~ΔFDE by AA.