Question

5.5.5 minVal Code hs help?

def minVal(x,y):
return x

x = minVal(10,14)
print("The min is" + str(x))
return

x = minVal (10,14)
print("The min is" + str(x))
return

Answer 1

It looks like you're trying to find the minimum value between two numbers, but your function currently just returns the first value (x). Here's how you can modify it:

```python
def minVal(x, y):
if x < y:
return x
else:
return y

x = minVal(10, 14)
print("The min is " + str(x))
```

This function will compare x and y and return the smaller number. Now when you call `minVal(10, 14)`, it will correctly print "The min is 10"

Answer 2

The minVal function in the student's query should compare two numbers and return the minimum. The provided code incorrectly always returns the first number. The correction includes a conditional statement to return the correct minimum value.

Step-by-step explanation:

The student is asking for help with a function in Python named minVal, which is intended to return the minimum of two numbers. However, the current code will always return the first argument x passed to the function, rather than the minimum of x and y. To fix the code and return the minimum value, the function should use a conditional statement to compare x and y, and return the smaller of the two.

Correct implementation of minVal function would look like this:

def minVal(x, y):
if x < y:
return x
else:
return y
x = minVal(10, 14)
print("The min is " + str(x))

With the given numbers 10 and 14, when this corrected code is executed, the output will be "The min is 10".