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SU is a midsegment of △RTV. If RV=z and SU=z–28, what is the value of z?

User Afron
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To find the value of z, we can use the fact that SU is a midsegment of triangle RTV.

Since SU is a midsegment, it divides the base RV into two equal segments. So, RV is equal to twice the length of SU.

Given that SU = z - 28, we can set up the equation:

RV = 2(SU)

z = 2(z - 28)

z = 56
User LostPhysx
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