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Write an equation in slope- intercept form of that passes through the given point and is parallel to the graph of the given equation (-9,-2);y=4x+2

User Neal Magee
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1 Answer

3 votes

Answer:

y = 4x + 34

Explanation:

To find an equation in slope-intercept form that passes through the point (-9, -2) and is parallel to the graph of the equation y = 4x + 2, we can use the fact that parallel lines have the same slope.

Since the given equation has a slope of 4, our parallel line will also have a slope of 4.

Using the point-slope form of a linear equation, we have:

y - y1 = m(x - x1)

Substituting the values (-9, -2) and m = 4, we get:

y - (-2) = 4(x - (-9))

Simplifying the equation gives us:

y + 2 = 4(x + 9)

Expanding further:

y + 2 = 4x + 36

To write the equation in slope-intercept form, we isolate y:

y = 4x + 36 - 2

Simplifying gives us:

y = 4x + 34

Therefore, the equation in slope-intercept form that passes through the point (-9, -2) and is parallel to the graph of y = 4x + 2 is y = 4x + 34.

User Shabnam
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