Register

Solve the equation for x. Assume a≠0. 5=5ax+1

Solve the equation for x. Assume a≠0. 5=5ax+1
145k views
5 votes
Solve the equation for x. Assume a≠0.




5=5ax+1

User Gawkface
by
8.2k points

1 Answer

5 votes
x=4/5a

5=5ax+1
Step 1: Multiply both sides by a.
5a=a+5x
Step 2: Flip the equation.
a+5x=5a
Step 3: Add -a to both sides.
a+5x+−a=5a+−a
5x=4a
Step 4: Divide both sides by 5.
5x/5=4a/5
x= 4/5a
User DopplerShift
by
8.6k points
← Prev Question Next Question →

Related questions

User Alanc Liu
asked Oct 13, 2024 165k views
8x-8+3ax=5ax-2a please help
Alanc Liu asked Oct 13, 2024
by Alanc Liu
8.6k points
1 answer
4 votes
165k views
User HaoQi Li
asked Feb 3, 2024 169k views
Differentiate y=5ax^(4)-2bx^(5), where a and b are constants.
HaoQi Li asked Feb 3, 2024
by HaoQi Li
8.1k points
1 answer
4 votes
169k views
User Manishoaham
asked Dec 10, 2024 147k views
5ax^3/(10bx^2) simplified
Manishoaham asked Dec 10, 2024
by Manishoaham
8.2k points
1 answer
0 votes
147k views
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
How do you estimate of 4 5/8 X 1/3
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
Link Copied!