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Two factory plants are making TV panels. Yesterday, Plant A produced 12,000 panels. Ten percent of the panels from Plant A and 3% of the panels from Plant B were defective. How many panels did Plant B produce, if the overall percentage of defective panels from the two plants was 6%?

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Answer:

Step-by-step explanation:To find out how many panels Plant B produced, we need to use the information given. Let's break it down step by step: 1. We know that 10% of the panels from Plant A were defective. This means that 10% of the 12,000 panels produced by Plant A were defective. - 10% of 12,000 = 0.10 * 12,000 = 1,200 defective panels from Plant A. 2. We also know that 3% of the panels from Plant B were defective. Let's assume the total number of panels produced by Plant B is "x". This means that 3% of "x" panels were defective. - 3% of x = 0.03 * x = 0.03x defective panels from Plant B. 3. The overall percentage of defective panels from the two plants is given as 6%. This means that the sum of the defective panels from Plant A and Plant B is 6% of the total number of panels produced. - 6% of the total number of panels = 0.06 * (12,000 + x) = 0.06 * (12,000 + x) defective panels from both plants. 4. We can set up an equation based on the information above: - 1,200 (defective panels from Plant A) + 0.03x (defective panels from Plant B) = 0.06 * (12,000 + x) (total defective panels from both plants) Now, we can solve this equation to find the value of "x", which represents the number of panels produced by Plant B.

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