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How much heat is required to raise the temperature of 8.0 g of solid water by 3.0 °C ?

User Charphacy
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Answer:

To calculate the amount of heat required to raise the temperature of a substance, you need to use the specific heat capacity formula:

q = m * c * ΔT

where:

q = heat energy

m = mass of the substance

c = specific heat capacity of the substance

ΔT = change in temperature

In this case, you are given:

m = 8.0 g (mass of solid water)

ΔT = 3.0 °C (change in temperature)

To find the specific heat capacity of solid water, you can use the value of the specific heat capacity of liquid water, which is approximately 4.18 J/g°C.

Now, let's plug in the values into the formula:

q = (8.0 g) * (4.18 J/g°C) * (3.0 °C)

First, multiply the mass (8.0 g) by the specific heat capacity (4.18 J/g°C), which gives you:

q = 33.44 J/°C

Then, multiply the result by the change in temperature (3.0 °C):

q = 33.44 J/°C * 3.0 °C

q = 100.32 J

Therefore, the amount of heat required to raise the temperature of 8.0 g of solid water by 3.0 °C is 100.32 Joules (J).

Step-by-step explanation:

User Joesph
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