Question

the sum of three consecutive intergers is 30 more than twice the smallest interger. Finf the sum of the first and last interger

Answer 1

The sum of the first and last integer is 56.

Explanation:

Let's call the three consecutive integers: x, (x + 1), and (x + 2).

According to the given information:

"The sum of three consecutive integers is 30 more than twice the smallest integer."

This can be expressed as an equation:

x + (x + 1) + (x + 2) = 2x + 30

Now, let's solve for x:

3x + 3 = 2x + 30

Subtract 2x from both sides:

3x - 2x + 3 = 2x - 2x + 30

x + 3 = 30

Subtract 3 from both sides:

x + 3 - 3 = 30 - 3

x = 27

So, the smallest integer is 27, and the three consecutive integers are 27, 28, and 29.

To find the sum of the first and last integer:

27 + 29 = 56

The sum of the first and last integer is 56.