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Solve for 4 where y is a real number (54-2)¹/³+3=0

User ArunPratap
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4 votes

Answer:

Explanation:

To solve for y in the equation (54 - 2)^(1/3) + 3 = 0, you need to isolate the expression with the exponent first:

(54 - 2)^(1/3) + 3 = 0

Now, subtract 3 from both sides of the equation:

(54 - 2)^(1/3) = -3

Now, let's simplify the left side:

(52)^(1/3) = -3

Now, take the cube root of both sides to solve for (52)^(1/3):

(52)^(1/3) = -3

2^(1/3) = -3

Now, raise both sides to the power of 3 to solve for 2:

2 = (-3)^3

2 = -27

User Tugra
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