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A person on Earth throws an object straight upwards from a height of 2.0 meters above the ground with an initial velocity upwards of 2.0 m/s. What is the maximum height above the ground that the object reaches?

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Answer:

the maximum height above the ground that the object reaches is approximately 2.204 meters.

Step-by-step explanation:

1. Identify the key values given in the problem:

- Initial height above the ground (h): 2.0 meters

- Initial velocity upwards (v₀): 2.0 m/s

2. Determine the maximum height using the formula for projectile motion:

- The maximum height (h_max) can be found using the formula: h_max = h + (v₀^2 / (2g))

- In this formula, g represents the acceleration due to gravity, which is approximately 9.8 m/s² on Earth.

3. Substitute the given values into the formula:

- h_max = 2.0 + (2.0^2 / (2 * 9.8))

4. Simplify the equation:

- h_max = 2.0 + (4.0 / 19.6)

- h_max = 2.0 + 0.204

5. Calculate the final answer:

- h_max = 2.204 meters (rounded to three decimal places)

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