Question

10) m_BCF = 13x + 2, mZBCD= 168°,
and mZFCD= 70x. Find m2BCF.
B
F

Answer 1

BCF + FCD = BCD

→13x + 2 + 70x = 168

→83x + 2 = 168

→83x = 166

→ x = 2