Explanation:
Using the uniform distribution, it is found that there is a 0.38 = 38% probability that X is between 0.68 and 1.44.
-----------------------
Uniform probability distribution:
Has two bounds, a and b.
The probability of finding a value between c and d is:
�
(
�
≤
�
≤
�
)
=
�
−
�
�
−
�
P(c≤X≤d)=
b−a
d−c
In this problem:
The bounds are 0 and 2, thus
�
=
0
,
�
=
2
a=0,b=2 .
The probability that X is between 0.68 and 1.44 is:
�
(
0.68
≤
�
≤
1.44
)
=
1.44
−
0.68
2
−
0
=
0.38
P(0.68≤X≤1.44)=
2−0
1.44−0.68
=0.38
0.38 = 38% probability that X is between 0.68 and 1.44.