Question

The right half of the square loop of wire shown in (Figure 1) is in a 0.65 T

magnetic field directed into the page. The current in the loop is 1.5 A
in a clockwise direction.
What is the magnitude of the force on the loop? F=?
In which direction does this force act?
upward
downward
to the left
to the right

Answer 1

The magnetic force on the square loop, with a current of 1.5 A in a 0.65 T magnetic field, is approximately 0.04875 N, and it acts to the right according to the right-hand rule.

To calculate the force on the square loop, we can use the formula for the magnetic force (F) on a current-carrying wire segment:

F = BIL

where:

B is the magnetic field strength,

I is the current, and

L is the length of the wire segment.

In this case, the length of each side of the square loop is given as 5 cm (or 0.05 m), and the current (I) is 1.5 A. The magnetic field (B) is 0.65 T.

Substitute these values into the formula:

F = (0.65 T) × (1.5 A) × (0.05 m)

F = 0.04875 N

So, the magnitude of the force on the square loop is approximately 0.04875 N.

Now, to determine the direction of the force, we can use the right-hand rule. If you point your thumb in the direction of the current (clockwise in this case), your index finger in the direction of the magnetic field (into the page), then your middle finger will point in the direction of the force. In this scenario, the force acts to the right.