Question

Calculate percent volume/volume of a solution that contains 80 ml of methanol and 230 ml of water?

Answer 1

To find the percent by volume of methanol in a solution with 80 ml of methanol and 230 ml of water, divide 80 by the total solution volume (310 ml) and multiply by 100 to get approximately 25.81% v/v.

Step-by-step explanation:

To calculate the percent volume/volume (% v/v) of a solution that contains 80 ml of methanol and 230 ml of water, we use the formula:

Percent by volume = (volume of solute / volume of solution) x 100%

In this case, the volume of the solute (methanol) is 80 ml and the volume of the solution is the sum of the volumes of methanol and water, which is 80 ml + 230 ml = 310 ml. Applying the formula:

Percent by volume = (80 ml / 310 ml) x 100%

So, the percent v/v of methanol in the solution is approximately 25.81%.

Answer 2

25.81%

Explanations:

The formula for calculating the percent volume/volume of a solution is given as:

`\%v\text{/v}.=\frac{volume\text{ of solute}}{volume\text{ of solution}}*100`

Given the following parameters

volume of solute (methanol) = 80mL

volume of solution = volume of water + methanol

volume of solution = 80mL + 230mL = 310mL

Determine the required percent v/v

`\begin{gathered} \%v\text{/}v=(80mL)/(310mL)*100 \\ \%v\text{/}v=(800)/(31) \\ \%v\text{/}v=25.81\% \end{gathered}`

Hence the percent volume/volume of a solution that contains 80 ml of methanol and 230 ml of water is 25.81%