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The population of Sasquatch in Salt Lake County was modeled by the function P(T)=500T/T+50, where T equals zero represents the year 1803. when were there fewer than 150 Sasquatch in Salt Lake County?

User Jacob B
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1 Answer

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Answer:there were fewer than 150 Sasquatch in Salt Lake County before the year 1824.

Explanation:

To determine when there were fewer than 150 Sasquatch in Salt Lake County, we need to find the values of T that make the population function, P(T), less than 150.

The population function is given by P(T) = 500T / (T + 50), where T represents the number of years since 1803.

To solve for T when P(T) is less than 150, we set up the inequality:

500T / (T + 50) < 150

To solve this inequality, we can multiply both sides by (T + 50) to get rid of the denominator:

500T < 150(T + 50)

Next, we distribute the 150 to both terms inside the parentheses:

500T < 150T + 7500

Combining like terms, we have:

500T - 150T < 7500

Simplifying further, we get:

350T < 7500

To isolate T, we divide both sides of the inequality by 350:

T < 7500 / 350

Calculating the division, we find:

T < 21.43

Since T represents the number of years since 1803, we round down to the nearest whole number to find the earliest year when there were fewer than 150 Sasquatch. Thus, T < 21.

To determine the year, we add T to 1803:

Year < 21 + 1803

Year < 1824

Therefore, there were fewer than 150 Sasquatch in Salt Lake County before the year 1824.

User Somnath Muluk
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