Question

How many moles of fe(no₃)₃ contain 6.91 × 10³⁶formula units of fe(no₃)₃?

Answer 1

`\huge{ \boxed{1.15 * {10}^(13) \: \text{moles}}}`

Step-by-step explanation:

The number of moles of
`Fe(NO_3)_3` can be found by using the formula;

`n = (N)/(L)`

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question;

N = 6.91 × 10³⁶ formula units

`\therefore \: n = \frac{6.91 * {10}^(36) }{6.02 * {10}^(23) } \\ = 1.15 * {10}^(13) \: moles`