Answer:
Therefore, the length of AB is approximately 6.3 units.
Step-by-step explanation: The distance formula is:
d = √((x2 - x1)^2 + (y2 - y1)^2)
Plugging in the given values, we get:
d = √((1 - (-1))^2 + (-2 - 4)^2)
d = √(2^2 + (-6)^2)
d = √(4 + 36)
d = √40
d ≈ 6.3
Therefore, the length of AB is approximately 6.3 units.