Final answer:
The correct choice to complete the proof of the isosceles triangle theorem is the side-angle-side (SAS) congruence postulate, as it justifies ΔABX being congruent to ΔCBX.
Step-by-step explanation:
The proof is confirming the principles of the isosceles triangle theorem, which states that if two sides of a triangle are congruent, then the angles opposite to those sides are also congruent. As stated in the proof, angle 2 is congruent to angle 2 by the definition of an angle bisector, and segment BX is congruent to itself by the reflexive property. To complete the proof, we observe that AB is congruent to CB by the given that BABC is isosceles, with AB and CB being the congruent sides. Thus, the congruent parts are: angle 2 is congruent (angle-angle), and BX is congruent to itself (side). These leave us with the side-angle-side (SAS) congruence postulate, justifying that ΔABX is congruent to ΔCBX. Hence, corresponding parts of congruent triangles are congruent, which means ∠A is congruent to ∠C.