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"A sample of 33 observations taken from an infinite population. The population proportion is .06, what is the probability that the sample proportion will be less than .1?"

User Sestocker
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1 Answer

2 votes

Answer:

Explanation:

First, let's calculate the mean and standard deviation of the sampling distribution using the population proportion (0.06) and the sample size (33):

Mean = Population proportion = 0.06

Standard deviation = sqrt((Population proportion * (1 - Population proportion)) / Sample size)

= sqrt((0.06 * (1 - 0.06)) / 33)

Next, we can standardize the sample proportion value of 0.1 using the z-score formula:

Z = (Sample proportion - Mean) / Standard deviation

= (0.1 - 0.06) / sqrt((0.06 * (1 - 0.06)) / 33)

Once we have the z-score, we can use a standard normal distribution table or calculator to find the corresponding probability.

For example, if the z-score is calculated to be 1.5, we would look up the area to the left of 1.5 in the standard normal distribution table, which corresponds to the probability of the sample proportion being less than 0.1.

Please note that I'm unable to provide the exact probability without knowing the specific z-score. However, you can use the steps outlined above to calculate the probability for your specific z-score.

User Joelreeves
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