Question

A 10-kg sign is held by two ropes as shown in the figure. What is the tension on rope A? A rectangular sign hangs on two ropes. Rope A extends from the top left corner of the sign upward and to the left at an angle of 45 degrees from the horizontal. Rope B extends from the top right corner of the sign upward and to the right at an angle of 30 degrees from the horizontal.

Answer 1

The magnitude of the tension in rope B is determined as 49 N.

How to calculate the tension in rope B?

The magnitude of the tension in rope B is calculated by applying the following formula as shown below;

TB = W x sin (θ)

where;

• W is the weight of the suspended object
• θ is the angle of inclination of rope B

The magnitude of the tension in rope B is calculated as follows;

TB = mg x sin (θ)

TB = 10 kg x 9.8 m/s² x sin (30)

TB = 49 N

Thus, the magnitude of the tension in rope B is determined as 49 N.