110k views
3 votes
Sac had a rope that was 15 feet long. He cut it into three pieces. The first piece was 3.57 feet longer than the second piece. The third piece was 2.97 feet longer than the second piece. How long was the third piece of rope?

1 Answer

5 votes

Answer:

5.79 feet

Explanation:

Let us represent

First piece = x

Second piece = y

Third piece = z

Sac had a rope that was 15 feet long.

x + y + z = 15

He cut it into three pieces.

The first piece was 3.57 feet longer than the second piece.

x = 3.57 + y

The third piece was 2.97 feet longer than the second piece.

z = 2.97 + y

How long was the third piece of rope?

x + y + z = 15

3.57 + y + y + 2.97 + y = 15

3y + 6.54 = 15

3y = 15 - 6.54

3y = 8.46

y = 8.46/3

y = 2.82 feet

Therefore, the length of the third piece z = 2.97 + y

z = 2.82 + 2.97

z = 5.79 feet

User Shalomb
by
6.0k points