Question

What is the initial value of the function:
f(x)=3/2(2)^x

Answer 1

It’s NONE. You can use symbolab

Answer 2

the initial value -- f(0) -- results in a value of 1.5

Explanation:

f(0) =
`(3)/(2)` ·
`2^(x)` (any value raised to the power of zero equals one)

f(0) =
`(3)/(2)` · 1

f(0) = 3/2 or 1.5