Answer:
x = 1
y = -2
z = -3
Explanation:
Okay, let's solve this system of equations:
3x + y + 2z = -10
x + 5y - 2z = -12
-2x + 3y = -1
To find x, y and z, we can use substitution.
Substituting the third equation into the first equation:
3x + y + 2z = -10
-2x + 3y = -1
-> x = 1
Substituting x = 1 into the second equation:
1 + 5y - 2z = -12
-> 5y - 2z = -13
-> 5y = -11 (subtracting -2z from both sides)
-> y = -11/5 = -2
Substituting x = 1 and y = -2 into the first equation:
3(1) - 2 + 2z = -10
-> 2z = -7
-> z = -7/2 = -3
Therefore, the solution is:
x = 1
y = -2
z = -3
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