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Solve the system of linear equations given below using substitution or elimination. 3x+2y=12 −x+y=11

User Lajosdeme
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1 Answer

6 votes

Answer:

x=−2 and y = 9y=9.

Explanation:

First, let's solve the second equation for x:

-x + y = 11−x+y=11

Adding xx to both sides:

y = x + 11y=x+11 (Equation 1)

Now we'll substitute this expression for y into the first equation:

3x + 2y = 123x+2y=12

3x + 2(x + 11) = 123x+2(x+11)=12 (Substitute y = x + 11y=x+11)

3x + 2x + 22 = 123x+2x+22=12

5x + 22 = 125x+22=12

Subtracting 22 from both sides:

5x = -105x=−10

Dividing both sides by 5:

x = -2x=−2

Now that we have the value of x, we can substitute it back into Equation 1:

y = x + 11y=x+11

y = -2 + 11y=−2+11

y = 9y=9

So, the solution to the system of equations is x = -2x=−2 and y = 9y=9.

User Ankostis
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