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Find the surface area of a closed box that is 5 m long, 4 m wide, and 8 m high. 1) 184 m2 2) 92 m2 3) 17 m2 4) 160 m2

User Saschpe
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Final answer:

The surface area of a closed box that is 5 m long, 4 m wide, and 8 m high, is calculated by adding the areas of all its faces, resulting in a total surface area of 184 m².

Step-by-step explanation:

To find the surface area of a closed box, we need to calculate the area of each of its six faces and then add them up. The formula for the surface area of a rectangular box is SA = 2lw + 2lh + 2wh, where l is the length, w is the width, and h is the height. Plugging in the given values, the surface area of the box is 2(5)(4) + 2(5)(8) + 2(4)(8) = 40 + 80 + 64 = 184 m².

The calculation to find the surface area of a closed box involves determining the area of all six sides of the box, then adding those values together. In this case, your box has dimensions of 5 m long, 4 m wide, and 8 m high. The formula for the surface area of a rectangular box is 2lw + 2lh + 2wh where l is the length, w is the width, and h is the height. Using these dimensions, we will get: 2(5m*4m) + 2(5m*8m) + 2(4m*8m) = 40 m² + 80 m² + 64 m² = 184 m². So, the surface area of the box is 184 m².

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User RidgeA
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