Question

In slope intercept form, what is the equation of the line (4,12)(-1,-13)

Answer 1

`(\stackrel{x_1}{4}~,~\stackrel{y_1}{12})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{-13}) ~\hfill~ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-13}-\stackrel{y1}{12}}}{\underset{\textit{\large run}} {\underset{x_2}{-1}-\underset{x_1}{4}}} \implies \cfrac{ -25 }{ -5 } \implies 5`

`\begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{12}=\stackrel{m}{5}(x-\stackrel{x_1}{4}) \\\\\\ y -12 = 5 x -20 \implies {\Large \begin{array}{llll} y = 5 x -8 \end{array}}`