117k views
5 votes
17. The equations y= −13x2 + 4 and y = x2 − 8 are graphed below. What are the solutions to the equation −13x2 + 4 = x2 − 8 ? A. X = -3 and x = 1 B. X = -3 and x = 3 C. X = 3 and x = -1 D. X = 3 and x = 1

17. The equations y= −13x2 + 4 and y = x2 − 8 are graphed below. What are the solutions-example-1

1 Answer

5 votes

Answer: the solutions to the equation -13x^2 + 4 = x^2 - 8 are:

A. x = -3 and x = 1

Step-by-step explanation: To find the solutions to the equation -13x^2 + 4 = x^2 - 8, we need to set the equation equal to 0 and solve for x.

-13x^2 + 4 = x^2 - 8

First, let's move all the terms to one side to get a quadratic equation in standard form:

-13x^2 - x^2 + 4 + 8 = 0

-14x^2 + 12 = 0

Next, let's solve the quadratic equation. We can use factoring or the quadratic formula. In this case, let's use factoring:

-14x^2 + 12 = 0

-2(7x^2 - 6) = 0

Now, we can set each factor equal to 0:

-2 = 0 (This is not possible, so we can ignore it.)

7x^2 - 6 = 0

Next, let's solve for x by factoring again:

7x^2 - 6 = 0

(7x - 3)(x + 2) = 0

Now, we can set each factor equal to 0 and solve for x:

7x - 3 = 0

7x = 3

x = 3/7

x + 2 = 0

x = -2

User Techfoobar
by
8.0k points