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Find the equation of the line that has a slope of 5 and passes through the point (-9,6)

User Ben Cawley
by
8.2k points

2 Answers

3 votes

Answer:

y = 5x + 51

Explanation:

You can use point-slope form to help you with this problem:

y - y1 = m(x - x1)

x1 is -9 , y1 is 6 and m is 5, we can plug those into the equation:

y - 6 = 5(x - (-9)

y - 6 = 5x + 45

Now add 6 to both sides:

y = 5x + 51

Our equation is y = 5x + 51

User Doug Coats
by
8.1k points
3 votes

Answer: y = 5x + 51

Explanation:

We can first create a point-slope form equation and then solve for y to create a slope-intercept form equation.

Given:

y - y1 = m(x - x1)

Substitute known values:

y - 6 = 5(x + 9)

Distribute the slope:

y - 6 = 5x + 45

Subtract 7 from both sides of the equation:

y = 5x + 51

User Marissa Fernandes
by
8.0k points

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