12.5k views
0 votes
Find the equation of the line parallel to Y=-2x-5 that include the point (-1,3)

1 Answer

1 vote

Answer:

Explanation:

To find the answer, we will use the point slope form, since we have both a slope (for 2 lines to be parallel, they must have the same slope, so if the original equation's slope is -2, so will our new one), and we have a point, (-1,3). So lets plug in the values together to the point slope equation (y-y1)=m(x-x1), where x1 and y1 are our "initial" x and y values, or well our desired point, in this case (-1,3), and m is just slope. So now, it'll be

y-(3)= -2(x-(-1)). First, we will apply the signs accordingly, remember 2 negatives make a positive, so y-3= -2(x+1). Now we will multiply so we will have it in slope intercept form, and we can do the last step after of isolating y.

y-3= -2x-2, and now add 3 to both sides, and now the final equation will be

y= -2x+1 !

User Shannon Kendrick
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories