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The air press, P millibars, at a distance of ‘n’ kilometres above sea level is given by this formula:

P=1013 x 0.88n

a) what is the air pressure at sea level?

b) by what percentage does the air pressure decrease for each kilometre above sea level?

User Scrhartley
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1 Answer

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Answer:

A) To find the air pressure at sea level, we can substitute n = 0 into the given formula:

P = 1013 x 0.88(0)

P = 0

Therefore, the air pressure at sea level is 0 millibars.

B) To find the percentage by which the air pressure decreases for each kilometer above sea level, we can compare the air pressure at two different altitudes. Let's consider an altitude of n kilometers and an altitude of (n + 1) kilometers.

For the altitude of n kilometers:

P1 = 1013 x 0.88n

For the altitude of (n + 1) kilometers:

P2 = 1013 x 0.88(n + 1)

To find the percentage decrease, we can use the formula:

Percentage decrease = [(P1 - P2) / P1] x 100

Substituting the values of P1 and P2:

Percentage decrease = [(1013 x 0.88n) - (1013 x 0.88(n + 1))] / (1013 x 0.88n) x 100

Simplifying the expression:

Percentage decrease = [1013 x 0.88n - 1013 x 0.88n - 1013 x 0.88] / (1013 x 0.88n) x 100

Percentage decrease = (- 1013 x 0.88) / (1013 x 0.88n) x 100

Percentage decrease = (-1) / n x 100

Percentage decrease = -100 / n

Therefore, the air pressure decreases by 100/n percent for each kilometer above sea level.

Explanation:

User Rmk
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