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A chess piece is placed on a random square of an 88 chess board. A second piece is then placed at random on one of the unoccupied squares.

Find the probability that:
a the two pieces lie on the same row
b the pieces lie on the same row or column
the pieces are adjacent to each other, either horizontally, vertically, or diagonally.

the answer is supposed to be 1/9, 2/9 and 5/48 i just don't know how to get it!

User Euvl
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1 Answer

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I apologize for any confusion. Let's go through each probability calculation step-by-step:

a) Probability that the two pieces lie on the same row:

- There are a total of 64 unoccupied squares on the chessboard for the second piece to be placed.

- Since the first piece is already placed on a random square, there are 8 possible squares in the same row for the second piece to be placed.

- Therefore, the probability that the two pieces lie on the same row is 8/64, which simplifies to 1/8.

b) Probability that the pieces lie on the same row or column:

- To calculate this probability, we need to consider the number of squares in the same row and column that the second piece can be placed on.

- Since there are 8 rows and 8 columns on the chessboard, there are a total of 16 possible squares (8 in the same row and 8 in the same column) for the second piece to be placed.

- However, we need to subtract 1 square from this count because the square where the first piece is placed is already occupied.

- Therefore, the probability that the pieces lie on the same row or column is (16 - 1)/64, which simplifies to 15/64.

c) Probability that the pieces are adjacent to each other:

- In this case, adjacent means horizontally, vertically, or diagonally neighboring squares.

- To calculate this probability, we need to consider the number of squares adjacent to the first piece.

- If the first piece is placed on one of the 4 corner squares, there are only 3 squares adjacent to it.

- If the first piece is placed on one of the 4 edge squares (excluding the corners), there are 5 squares adjacent to it.

- If the first piece is placed on any of the remaining 36 squares in the center of the board, there are 8 squares adjacent to it.

- Therefore, the total number of favorable outcomes is (4 corners * 3 adjacent squares) + (4 edge squares * 5 adjacent squares) + (36 center squares * 8 adjacent squares) = 12 + 20 + 288 = 320.

- The total number of possible outcomes remains the same, which is 64 (the number of unoccupied squares on the board).

- Hence, the probability that the pieces are adjacent to each other is 320/64, which simplifies to 5/8.

In summary:

a) The probability that the two pieces lie on the same row is 1/8.

b) The probability that the pieces lie on the same row or column is 15/64.

c) The probability that the pieces are adjacent to each other is 5/8.

If you have a different set of correct answers, please provide the necessary information so I can assist you further.

User Hzz
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