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Find two solutions for this equation (x-5)(x-3)=0

User TykiMikk
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Answer:

The equation (x-5)(x-3) = 0 can be solved by finding the values of x that make the equation true.

To do this, we set each factor equal to zero and solve for x:

x - 5 = 0 --> x = 5

x - 3 = 0 --> x = 3

So, the two solutions to the equation (x-5)(x-3) = 0 are x = 5 and x = 3.

These values of x make the equation true because when we substitute them back into the equation, we get (5-5)(5-3) = 0 and (3-5)(3-3) = 0, which simplify to 0 = 0.

In this case, the equation represents two intersecting lines on a graph, with x = 5 and x = 3 as the points where the lines cross the x-axis.

Explanation:

User Kolmar
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