Explanation:
distance / rate = time
x = original speed mph
60/x = t
Then at 5 mph faster
60/(5+x) = t - 6 re-arranged for t = 60/(5+x) + 6
equate the two definitions of 't' then solve for 'x'
60/x = 60/(5+x) + 6
60 = 60x/(5+x) + 6x
60(5+x) = 60x +6x(5+x)
300 + 60x = 60x + 30x + 6x^2
6x^2 +30x -300 = 0 Use Quadratic Formula to find x = 5 m/hr