Question

Someone do number 1 please

Answer 1

PAF rectangle en F

PA²=AF²+FP²

25²=15²+FP²

FP²=25²-15²

FP = √400=20

height of flagpole=20m

b) sin∠B=PF/PB=20/25=0,8

∠B=53,130102..=53°

Explanation:

Answer 2

a. Height of the flagpole = 20 meters

b. Angle between PB and AB = 53.13°

Explanation:

Part A

Given:

• AB = 30 meters
• A F = AB/2 = 15 meters
• PA = 25 meters

To find:

Height of the flagpole F P

Solution:

Using the Pythagorean Theorem, we can solve for the height of the flagpole, F P:

`\sf F P^2 = AP^2 - A F^2`

`\sf F P^(2)= 25^2 - 15^2`

`\sf FP^2 = 400`

`\sf F P = √(400)`

F P = 20 meters

Therefore, the height of the flagpole is 20 meters.

Part B

To find:

• The angle between PB and AB

Solution:

We can use the trigonometric ratio cosine to solve for the angle between PB and AB. Cosine is defined as the adjacent side over the hypotenuse. In this case, the adjacent side is PB and the hypotenuse is AB.

Therefore, we can use the following equation:

`\sf cos(B) =( PB )/(AB)`

We know that PB = 15 meters and AB = 25 meters, so we can substitute these values into the equation:

`\sf cos (B) =(15)/(25)`

`\sf \angle B = cos^(-1)\left((20)/(15)\right)`

`\sf \angle B \approx 53.13^\circ`

Therefore, the angle between PB and AB is 53.13°.