Question

Can someone do Question 2 please

Answer 1

Rectangle D ADC

Pythagore's theorem

AC²=AD²+DC²

AC² = 6.6²+6.5²

AC²= 84.5

AC = √84.5 = (13√2)/2≈9.192388...≈9.2cm

ACD rectangle in C:

AB²=AC²+CB²

AB²=84.5+8.4²

AB²=155.06

AB = √155.06≈12.452309...≈12.5cm

Answer 2

AC = 9.2 m

AB = 12.5 m

Explanation:

Since the given triangle are right angled triangle.

We can find the needed sides by using the Pythagorean theorem.

The Pythagorean theorem is a fundamental relation in Euclidean geometry among the three sides of a right triangle. It states that the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In other words, if a and b are the lengths of the legs of a right triangle, and c is the length of the hypotenuse, then:

`\sf a^2 + b^2 = c^2`

In Left Triangle:

a = b = 6.5 m

c = AC

Using Pythagorean theorem:

we get

6.5² + 6.5² = c²

84.5 = c²

`c =√(84.5)`

c = 9.2 m approximately

Therefore, AC = 9.2 m

Similarly

In Right-Up Triangle:

a = 9.2 m

b = 8.4m

c = AB

Using Pythagorean theorem:

we get

9.2² + 8.4² = c²

155.2 = c²

`c =√(155.2)`

c = 12.5 m approximately

Therefore, AB = 12.5 m