Answer:To determine the number of grams of sucrose needed to make a 39.0% (w/v) sucrose solution in 715 mL, we can follow these steps:
1. Understand the meaning of a 39.0% (w/v) sucrose solution:
- A 39.0% (w/v) sucrose solution means that 39.0 grams of sucrose are dissolved in 100 mL of solution.
2. Calculate the amount of sucrose needed for 100 mL of solution:
- If 39.0 grams of sucrose are dissolved in 100 mL of solution, we can set up a proportion to find the amount of sucrose needed for 1 mL of solution:
39.0 grams / 100 mL = x grams / 1 mL
3. Calculate the amount of sucrose needed for 715 mL of solution:
- To find the amount of sucrose needed for 715 mL of solution, we can use the proportion we set up in step 2 and solve for x:
39.0 grams / 100 mL = x grams / 1 mL
x = (39.0 grams / 100 mL) * 715 mL
4. Calculate the number of grams of sucrose needed:
- Now, we can substitute the given values into the equation:
x = (39.0 grams / 100 mL) * 715 mL
x ≈ 277.35 grams
Therefore, approximately 277.35 grams of sucrose are needed to make 715 mL of a 39.0% (w/v) sucrose solution.
Step-by-step explanation: