Question

Lindsey kept track of the cost of her lunches each day for a month. The data formed a consistent pattern, which enabled it to be graphed as the uniform density curve shown. A uniform density curve titled Lunch Costs has cost (dollars) on the x-axis, and relative frequency on the y-axis. A line is horizontal at y = 0.4 from 6 to 8.5. Everything under the line is shaded blue, and the area from 7 to 8 is shaded orange. Suppose a lunch is selected at random from the population of lunch costs. The probability that the lunch costs between $7 and $8 is .

Answer 1

Answer: So, the probability that a randomly selected lunch costs between $7 and $8 is 0.4, or 40%.

Explanation:

To find the probability that a randomly selected lunch costs between $7 and $8, you can calculate the area under the uniform density curve between those two values.

In this case, the uniform density curve is represented as a rectangle with a height of 0.4 (y = 0.4) and a base of 8 - 7 = 1 dollar (the width of the interval from $7 to $8).

The probability is equal to the area of the shaded region, which is a rectangle in this case.

Probability = Area of rectangle = (height) * (width) = (0.4) * (1) = 0.4

So, the probability that a randomly selected lunch costs between $7 and $8 is 0.4, or 40%.