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Given sm of arithmetic series Sn=n²-2n .find 13th of the series

User Ionpoint
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Answer:

To find the 13th term of the arithmetic series, we need to use the formula for the sum of the first n terms:

Sn = n/2 * (a1 + an)

where Sn is the sum of the first n terms, a1 is the first term, and an is the nth term.

We are given that Sn = n² - 2n. To find an expression for the nth term, we can use the formula for the sum of an arithmetic series:

Sn = n/2 * (a1 + an)

n² - 2n = n/2 * (a1 + an)

Simplifying and rearranging:

an = n/2 * (a1 + an) - n² + 2n

an - n/2 * an = n/2 * a1 - n² + 2n

(1 - n/2) * an = n/2 * a1 - n² + 2n

an = (n/2) * (2a1 - n + 2)

Now we can substitute n=13 to find the 13th term:

a13 = (13/2) * (2a1 - 13 + 2)

a13 = 6.5 * (2a1 - 11)

We cannot determine a13 without knowing the value of a1.

Explanation:

User Arnold Zahrneinder
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