Fom the question, the following can be derived:
Ticket price = $3
Winning price = $1000
Probability of winning (Pwin) = (1/200)
Probability of not winning (Ploss) = [1 - (1/200)] = 199/200
The net income if Raul wins (Nwin) = $1000 - $3 = $997 (when there is no refund)
The net loss if Raul does not win (Nloss) = -$3
(a) We are to determine his expected value:
To determine his expected value, we using this:
(Pwin * Nwin) + (Ploss * Nloss)
((1/200) * 997) + ((199/200) * -3)
4.985 - 2.985 = 2
The expected value is 2.
(b) We are also to determine the fair price of a ticket
To get the fair price of a ticket, we will add the cost of ticket and the expected value:
Cost of ticket + Expected value
3 + 2 = 5
Therefore, the fair price of a ticket is 5.