Question

Find the equation of the line with the given slope that passes through

the given point. Write the equation of the line in point-slope form.

1. m = 2 and (-1, -3) 2. m = -7 and (1, -1)

3. m = -2 and (-5, -2) 4. m = 6 and (2, 5)

5. m = 3 and (0, 10) 6. m = -9 and (8, 9)

7. m = -1 and (-6, 12) 8. m = 0 and (3, 7)

Find the equation of the line that passes through the given points. Write
the equation in point-slope form.

9. (-1, 3) and (-2, 5) 10. (-7, 7) and (5, -6)

11. (1, 12) and (-3, 5) 12. (1, 9) and (-2, -2)

13. (-6, 10) and (2, -5) 14. (-8, 7) and (-3, -5)

15. (-3, 3) and (4, 10) 16. (0, 9) and (-2, 11)

Answer 1

Explanation:

equation of the line in point - slope form is,

y = mx + b

for questions 1 - 8

given are the slope, m and x, y co - ordinates let's use these values to find constant b

1.

-3 = 2(-1) + b

-3 + 2 = b

b = -1

thus, the equation of the line is,

y = 2x - 1

7.

12 = -1(-6) + b

12 = 6 + b

12 - 6 = b

b = 6

thus, the equation of the line is,

y = -x + 6

8.

7 = 0(3) + b

7 = 0 + b

b = 7

thus, the equation of the line is,

y = 7

for questions 9 - 16

given are the x, y co - ordinates x1, y1 and x2, y2 we will use these values to find the slope, m and constant, b

9.

slope, m = y2 - y1 / x2 - x1

= 5 - 3 / -2 + 1

= 2/-1 = -2

let's take x1, y1 as x, y co - ordinate to find the constant, b

3 = -2(-1) + b

3 = 2 + b

3 - 2 = b

b = 1

thus, the equation of the line is,

y = -2x + 1

15.

slope, m = y2 - y1 / x2 - x1

= 10 - 3 / 4 + 3

= 7/7 = 1

let's take x1, y1 as x, y co - ordinate to find the constant, b

3 = 1(-3) + b

3 = -3 + b

3 + 3 = b

b = 6

thus, the equation of the line is,

y = x + 6