Final answer:
The work done by the 200-N force on a cart is 2000 J, and the work done by the friction acting against the motion of the cart is -900 J.
Step-by-step explanation:
The subject of this question is Physics, specifically, it involves calculations related to work, force, and friction. (a) The work done by the 200-N force on the 55-kg cart can be calculated using the formula for work: work = force x distance. Given that the force is 200 N and the distance is 10 m, the work done would be (200 N) x (10 m) = 2000 Joules. This assumes that the force is applied in the same direction that the cart moves.
(b) The work done by the force of friction is also found using the formula work = force x distance, but need to find the force of friction first. This force of friction opposes the motion of the cart and can be calculated using Newton's Second Law (F=ma), by subtracting the force of friction from the applied force (200 N). Therefore, frictional force = applied force - (mass x acceleration) = 200 N - (55 kg x 2 m/s²) = 90 N. Now that we have the frictional force, multiplying by the distance results in work done by friction = frictional force x distance = 90 N x 10 m = 900 Joules. Note that this is negative work due to the direction of the force (opposing the motion of the cart).
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