Answer:
let two number be x and y
by question
x+y=5….....(1)
xy=6
x=6/y.........(2)
putting the value of x in equation 1
6/y+y=5
6+y²=5×y
y²-5y+6=0
y²-3x-2x+6=0
(y-3)(y-2)=0
either
y=3
or
y=2
:.required no is 2 and 3
13
Explanation:
the two numbers that satisfy the requirements for this is 2 and 3, so the answer i put is the sum of the square of the two numbers.
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