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14y^2 - 21x = a(2y^2 - 3x) what is the value of a

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Answer:

Hi,

Explanation:

To find the value of a, we can compare the coefficients of y² and x on both sides of the equation

14y²−21x=a(2y²−3x)

First, let's compare the coefficients of y² on both sides:

On the left side, the coefficient of y² is 14.

On the right side, the coefficient of y² is 2a.

For the equation to be true, these coefficients must be equal, so:

14=2a

Now, solve for aa:

2a=14

a=14/2

a=7

So, the value of a is 7.

User Alexandr Belov
by
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