Answer:
To find the volume of 3 moles of gas at a pressure of 5.2 atm and a temperature of 120 K, you can use the ideal gas law:
PV = nRT
Where:
P = pressure (in atmospheres)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature (in Kelvin)
Now, plug in the values:
P = 5.2 atm
n = 3 moles
R = 0.0821 L·atm/(mol·K)
T = 120 K
PV = nRT
V = (nRT)/P
V = (3 moles * 0.0821 L·atm/(mol·K) * 120 K) / 5.2 atm
V = (29.748 L·atm) / 5.2 atm
V ≈ 5.73 liters
So, the volume of 3 moles of gas at a pressure of 5.2 atm and a temperature of 120 K is approximately 5.73 liters.