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What is the vertex of the quadratic function given by the equation f(x)=(x-3)^2+5

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The vertex of a quadratic function in the form f(x) = (x - h)^2 + k is given by the coordinates (h, k). In your case, the equation is f(x) = (x - 3)^2 + 5, so the vertex is at (h, k) = (3, 5). Therefore, the vertex of the given quadratic function is (3, 5).

if its wrong, sorry i tried :)

User Lucianne
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