Question

the perimeter of a rectangle is 30 m. The length is 3 m more than three times the width. Find the length and the width of the rectangle

Answer 1

`\textsf{length = 12m and width = 3m}`

Explanation:

`\sf\\\textsf{Let the length and width of rectangle be 'l' and 'w' respectively.}\\Now,\\\textsf{Case 1(Perimeter of rectangle = 30m): }\\2(l+w)=30\\or,\ l+w=15\\or,\ l=15-w........(1)`

`\sf\\\textsf{Case 2(length = 3 x width +3m):}\\l=3w+3\\\textsf{Substituting equation(1),}\\15-w=3w+3\\\textsf{or, }12=4w\\\textsf{or, }w=3m`

`\sf\\l=15-w=15-3=12m`

`\textsf{So the length of rectangle is 12m and the width is 3m.}`