Answer:
U(2, 7) → U'(-7, 2)
V(10, 7) → V'(-7, 10)
W(2, 3) → W'(-3, 2)
Explanation:
From the picture attached,
Coordinates of the vertices of the given triangle,
U → (2, 7)
V → (10. 7)
W → (2, 3)
Since rule for the coordinates of a point P(x, y) after a rotation of 90° counterclockwise about the origin is,
P(x, y) → P'(-y, x)
Here point P is the preimage and P' is the image point after rotation.
By this rule,
U(2, 7) → U'(-7, 2)
V(10, 7) → V'(-7, 10)
W(2, 3) → W'(-3, 2)