Question

Pls help due in soon

Answer 1

x | -1 | 0 | 1 | 2 | 3

y | -7 | -4 | 3 | 14 | 29

Explanation:

To complete the table of values, y = 2x^2 + 5x - 4,let's substitute each given x-value into the equation and solve for y.

Let's calculate the corresponding y-values for each x-value :

When x = -1:-

`\sf y = 2* (-1)^2 + 5* (-1) - 4\\\\ = 2* 1 - 5 - 4\\\\ = 2 - 5 - 4\\\\=\boxed{ -7}`

When x = 0:

`\sf y = 2* (0)^2 + 5*(0) - 4\\ \\= 0 + 0 - 4\\ \\=\boxed{ -4}`

When x = 1:

`\sf y = 2* (1)^2 + 5* (1) - 4 \\ \\= 2* 1 + 5 - 4 \\\\= 2 + 5 - 4 \\\\=\boxed{ 3}`

When x = 2:

`\sf y = 2* (2)^2 + 5* (2) - 4\\\\ = 2*4 + 10 - 4\\\\ = 8 + 10 - 4\\ \\= \boxed{14}`

When x = 3:

`\sf y = 2* (3)^2 + 5* (3) - 4\\\\= 2* 9 + 15 - 4\\\\= 18 + 15 - 4 \\\\=\boxed{ 29}`

Therefore, the completed table of values is as follows:

x | y

-1 | -7

0 | -4

1 | 3

2 | 14

3 | 29

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Hope this helps!

Answer 2

Plug the values in!

Explanation:

Just plug the values in the equation.

-7, -4, 3, 14, 29