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Maths question. Question is in the picture

Maths question. Question is in the picture-example-1
User Mbarlocker
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1 Answer

5 votes

Explanation:

there are two side lengths missing : the top vertical side between (2p - 1) and (p - 1). let's call it x. and the lower middle horizontal side between (p + 1) and p. let's call it y.

we see that the long vertical side in the right covering all 3 sub-rectangles is (4p - 2).

on the left side we have as vertical sides p and (p + 1) and then our missing side. all 3 together must be the same as (4p - 2) :

4p - 2 = p + (p + 1) + x = 2p + 1 + x

x = 2p - 3

and we see that the total horizontal length of the object is

(2p - 1) + (p - 1) = 3p - 2

and that must be the same as the total horizontal length on the lower side

3p - 2 = (p + 3) + y

y = 2p - 5

(i)

the perimeter is then

(4p-2) + (p+3) + p + (2p-5) + (p+1) + (2p-1) + (2p-3) + (p-1) =

= 14p -8

(ii)

the area is the sum of the 3 sub-rectangles :

(p-1)(2p-3)

(p+1)((2p-1) + (p-1)) = (p+1)(3p-2)

p(p+3)

(p-1)(2p-3) = 2p² - 3p - 2p + 3 = 2p² - 5p + 3

(p+1)(3p-2) = 3p² - 2p + 3p - 2 = 3p² + p - 2

p(p+3) = p² + 3p

the sum of these 3 terms is the total area

2p² - 5p + 3 + 3p² + p - 2 + p² + 3p =

= 6p² - p + 1

User Bobbybouwmann
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