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A) Fill in the gaps to factorise the

expression below.
x² + 9x
b) Use your answer to part a) to solve
x² + 9x - 10 = 0
10 =
(x − _)(x + —)

User Megajin
by
7.0k points

1 Answer

3 votes

Answer:

So the solutions to the equation x² + 9x - 10 = 0 are x = 0 and x = -9.

To find the missing numbers in the factorized form (x − _)(x + —), we need to determine the numbers that, when multiplied, give -10 and, when added, give 9. In this case, the numbers are -10 and 1, since -10 * 1 = -10 and -10 + 1 = 9. Therefore, the factorized form is:

(x − 1)(x + 10)

Explanation:

A) To factorize the expression x² + 9x, we can look for common factors. In this case, both terms have an x, so we can factor out an x:

x(x + 9)

B) Now, let's use the answer from part A to solve the equation x² + 9x - 10 = 0. We can rewrite the equation as:

x(x + 9) - 10 = 0

Expanding the expression, we get:

x² + 9x - 10 = 0

Since we already have the expression in factored form, we can set each factor equal to zero:

x = 0

x + 9 = 0

Solving for x in each equation, we find:

x = 0

x = -9

So the solutions to the equation x² + 9x - 10 = 0 are x = 0 and x = -9.

To find the missing numbers in the factorized form (x − _)(x + —), we need to determine the numbers that, when multiplied, give -10 and, when added, give 9. In this case, the numbers are -10 and 1, since -10 * 1 = -10 and -10 + 1 = 9. Therefore, the factorized form is:

(x − 1)(x + 10)

User Kilogram
by
8.2k points

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